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Tuesday 6 October 2020

notes on Heredity

 Heredity 

Heredity refers to the transmission of characters from parents to offsprings. An inherited trait is a particular genetically determined feature that distinguishes a person from the others for example; attached or free ear lobes in human beings.

Mendel selected garden pea Pisum sativum plant for his experiments because of the following characteristics:

(i) The flowers of this plant are bisexual. 
(ii) They are self-pollinating, and thus, self and cross pollination can easily be performed. 
(iii) The different physical characteristics were easy to recognise and study. 
(iv) They have a shorter life span and are the plants are easier to maintain.


Rules for the inheritance of traits:
Mendel’s contribution: The rules for inheritance of traits in human beings are related to the fact that both mother and father contribute an equal amount of genetic material i.e. DNA to their offspring. So an offspring will get two versions of that trait from the two parents. Mendel worked out rules for inheritance of these traits. Gregor Johann Mendel regarded as the ‘Father of Genetics’ performed his experiments with garden peas (Pisum sativum) in the garden behind his monastery. He observed a number of contrasting characters in garden peas and observed their inheritance.

Some important terms
1. Chromosomes are long thread-like structures present in the nucleus of a cell which contain hereditary information of the cell in the form of genes.

2. DNA is a chemical in the chromosome which carries the traits in a coded form.

3. Gene is the part of a chromosome which controls a specific biological function.

4. Contrasting characters: A pair of visible charactes such as tall and dwarf, white and violet flowers, round and wrinkled seeds, green and yellow seeds etc.

5. Dominant trait: The character which expresses itself in a (Ft) generation is dominant trait. Example : Tallness is a dominant character in pea plant.

6. Recessive trait: The character which does not express itself but is present in a generation is recessive trait. Ex. dwarfism in the pea plant.

7. Homozygous: A condition in which both the genes of same type are present for example; an organism has both the genes for tallness it is expressed as TT and genes for dwarfness are written as tt.

8. Heterozygous: A condition in which both the genes are of different types for example; an organism has genes Tt it means it has a gene for tallness and the other for dwarfness only tall character is expressed.

9. Genotype: It is genetic make up of an individual for example; A pure tall plant is expressed as TT and hybrid tall as Tt.

10. Phenotype: It is external appearance of the organism for example; a plant having Tt composition will appear tall although it has gene for dwarfness.

11. Homologous pair of characters are those in which one member is contributed by the father and the other member by the mother and both have genes for the same character at the same position.

Mendel’s Experiment: Mendel started his experiment on the pea plants. He conducted first monohybrid and then dihybrid crosses.



he took pure tall (genotype TT) and pure dwarf (genotype tt) pea plants and cross pollinated them to obtain first generation or first filial generation. In this figuration (F1 generation) he obtained only tall plants. This meant that only one of the parental traits was seen, not the mixture of the two. The plants of F generation or progeny are then self pollinated to obtain F2 generation or progeny. Now all plants were not tall. He obtained 75% tall plants and 25% dwarf plants i.e. the phenotypic ratio was 3:1. This indicates that in the F, generation both tall and dwarf traits were inherited but tallness expressed it self. Tallness is a dominant trait and dwarfness is a recessive trait. F2 generation has a genotypic ratio of 1 : 2 : 1 of three types of plants represented by TT, Tt and tt as shown in the cross.

Conclusion: Phenotypic ratio—Tall : Dwarf 3 : 1
Genotype ratio—Pure Tall : Hybrid Tall : Pure Dwarf 1 : 2 : 1

Law of Dominance: When parents having pure contrasting characters are crossed then only one character expresses itself in the Ft generation. This character is the dominant character and the character/factor which cannot express itself is called the recessive character.

Dihybrid Cross: Mendel also carried out experiments to observe inheritance of two pairs of contrasting characters, which is called dihybrid cross. He cross breed pea plants bearing round green seed with plants bearing wrinkled and yellow seeds. In the Fx generation he obtained all round and yellow seeds it means round and yellow traits of seeds are dominant features while wrinkled and green are recessive. He self-pollinated the plants of F: generation to obtain F2 generation, he obtained four different types of seeds round yellow, round green, wrinkled yellow and wrinkled green in the ratio of 9 : 3 : 3 : 1. He concluded that traits are independently inherited

Conclusion

  • Round and yellow seeds-9.
  • Round and green seeds-3.
  • Wrinkled and yellow seeds-3.
  • Wrinkled and green seeds-1.
  • How do traits get expressed?
    Cellular DNA is the information source for making proteins in the cell.
    A part of DNA that provides information for one particular protein is called a gene for that protein for example; the height of a plant depends upon the growth hormone which is in turn controlled by the gene. If the gene is efficient and more growth hormone is secreted the plant will grow tall. If the gene for that particular protein gets altered and less of it is secreted when the plant will remain short. Both the parents contribute equally to the DNA of next generation during sexual reproduction. They actually contribute a copy of the same gene for example; when tall plant is crossed with short plant the gametes will have single gene either for tallness or for shortness. F1 generation will get one gene for tallness and other for shortness also.
    Heredity and Evolution Class 10 Notes Science Chapter 9 2

How do germ cells i.e. gametes get single set of genes from parents who have two copies in them ?
Each gene set is present, not as a single long thread of DNA, but as separate independent pieces each called a chromosome. Each cell gets two copies of the chromosome, one from each parent. Each germ cell or gamete has one copy of it because there is reductional division in the sex organs at the time of formation of gametes. When fertilization takes place normal number of chromosomes is restored in the progeny ensuring the stability of DNA of the species.

How is the sex of a newborn individual determined?
It is the process by which sex of a newborn can be determined.

Different species use different strategies for this :

  • In some animals the temperature at which fertilized eggs are kept determines whether the developing animals will be males or females.
  • Some animals like snails can change sex indicating that sex is not genetically determined.
  • In human beings sex of the individual is determined genetically; means genes inherited from the parents decide the sex of the offspring.

  • Sex determination in human beings: In human beings, all chromosomes are not paired. 22 chromosomes are paired but one pair called sex chromosome is odd in not having a perfect pair in males. Females have a perfect pair both represented by XX. On the other hand males have a normal sized X but the other is short called Y so it is shown as XY. All gametes or ova formed by the homogenetic female are similar i.e. have X chromosome. Males heterogenetic form two types of sperms i.e. half with X chromosome and the other half with Y chromosome. Sex of the baby will depend on fertilization. There are two possibilities :
    Heredity and Evolution Class 10 Notes Science Chapter 9 3

    Autosomes: Those chromosomes which do not play any role in sex determination.

    Sex chromosomes: Those chromosomes which play a role in determining sex of the newborn.

    • If the sperm having X chromosome fertilizes with ovum with X chromosome then the baby will have XX chromosome and it will be female.
    • If the sperm having Y chromosome fertilizes with ovum with X chromosome then the baby will have XY chromosomes and it will be male.
    • Remember!
      Variations are produced both in sexual and asexual reproduction but amount of variations produced in asexual reproduction are subtle (so little) that they are hardly noticeable as compared to variations caused due to sexual reproduction.

      4. Genotype : The genetic constitution of an organism e.g., Genotype of human male is 44 + XY and
      genotype of human female is 44 + XX

      5. Phenotype : The appearance of the organism, i.e., the way in which genotype is expressed. Phenotype is the result of interaction of genes with the environment.
      e.g., Red colour may be controlled by a pair of genes RR. Now if genotype is RR phenotype will be red only but if genotype is Rr then also phenotype will be red since R is a dominant gene.

      6. Gene : It is the basic unit of inheritance by which characters are transferred from parents to their offspring. Gene consists of a specific length of DNA on a chromosome. A specific Segment of DNA that provides the information for one protein is called gene for that protein.
      According to Mendel, both parents must contribute equally to the DNA of the progeny during sexual reproduction. As both parents determine the trait in the progeny, so both parents must be contributing a copy of the same gene.

      7. Chromosomes : These are the long threads present in the nucleus of every cell. Chromosomes are made- up of DNA and protein. Each chromosome contains very long molecule of DNA.
      Remember!
      Each gene set is present as separate independent pieces each called a chromosome. Each cell have two copies of each chromosome, one each from male and female parents. Every germ cell will take one chromosome from each pair and these may be of either maternal or paternal origin. When two germ cells combine, they will restore the normal number of chromosomes in the progeny, ensuring the stability of the DNA of the species. Such mechanism of inheritance is used by all sexually and asexually reproducing organisms.

      8. Allele: It is an alternative form of a gene occupying the same position on a chromosome and affecting the same characters but in two alternative ways, e.g., the free and attached ear lobe are the alleles of ear lobe character.
      Expressing allele of a gene :

      • Homozygous dominant in capital letters, e.g., tallness(TT)
      • Homozygous recessive in smalMetters, e.g., shortness or dwarfness (tt)
      • Heterozygous (Tt)-lt will be called hybrid tall.

      9. Dominant allele: An allele that affects the phenotype of an organism both in heterozygous and homozygous condition. It is denoted by a capital letter, e.g., tallness in pea plant is denoted by ‘T.

      10. Recessive allele: An allele that affects the phenotype of the organism in absence of a dominant allele, i.e., in homozygous recessive individuals. It is denoted by a small alphabet, e.g., dwarfness in pea plant is denoted by’t’.

      11. Homozygous: When both alleles of a particular gene are the same, e.g., TT

      12. Heterozygous : When both alleles of a particular gene are different, e.g., Tt

      13. Diploid : Cells or organism containing two sets of genes, e.g., human body cells. Diploid cells have genetic constitution of 2n.

      14. Haploid : Cells or organism containing one set of genes, e.g., human reproductive cells (sperms and ova). Haploid cells have genetic constitution of n.

      15. Monohybrid cross : A cross between two parents taking the alternative traits of one single character, e.g., A cross between tall and dwarf pea plants.
      Monohybrid Ratio :

      • In F1 generation : 100% hybrid
      • In F2 generation : phenotypic ratio is 3 : 1 and genotypic ratio is 1 : 2 : 1

      16. Dihybrid cross: A cross between two parents taking into consideration alternative traits of two different characters, e.g., A cross between two pea plants one having round, green seeds and the other having wrinkled, yellow seeds.
      Dihybrid Ratio :

      • F1 ratio is 100% Hybrid type.
      • F2 ratio : Phenotypic is 9 : 3 : 3 : 1 and Genotypic . ratio is very complex.

      17. Human Blood Groups: There are four types of blood groups A, B, AB or O. These are controlled by a gene which is denoted by symbols IA, IB and IO (sometimes also denoted as i). The genes IA and IB show no dominance over each other (they are codominant, i.e., both expresses themselves independently). But these both genes are dominant over the gene IO. Therefore, blood group of a person depends on the type of genes present, e.g., (i) Blood group A has the following gene types :
      heredity-and-evolution-cbse-notes-for-class-10-science-1

      18. Determining sex of a newborn individual genetically:

      • In human beings the sex of the individual is ” determined genetically.
      • There are 23 pairs of chromosomes of which 22 are similar in male and female and are known as autosomes.
      • The remaining one is sex chromosome which is XY in males and XX in females.
      • Males produce two types of sperms X and Y, while female produces one type of egg X.
      • If a X type of sperm fertilizers the egg then the sex of baby will be female (XX).
      • If Y type of sperm fertilizers the egg then the sex of the baby will be male (XY).
        heredity-and-evolution-cbse-notes-for-class-10-science-2

      19. Mendel’s experiment to show that traits may be dominant or recessive:

      • Mendel conducted breeding experiments in garden pea.
      • selected pure plant of a tall/short plant.
      • produced first generation plants by crossing them.
      • found that all plants were tall.
      • produced the second generation by self-fertilization of hybrids.
      • found that three-quarter of the plants was tall and one quarter was short.
        heredity-and-evolution-cbse-notes-for-class-10-science-3

72 comments:

  1. Recieved answer sheet
    And seen our mistakes
    Watched olab activities
    Sneha Saraogi
    X G

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  2. Recieved biology paper mam. Seen my mistakes. Thank you mam

    Chehak Oberoi
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  3. I have got mam bio paper and seen my mistake.
    O Lab activity done in class
    Om Raghav
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  4. Thank you ma'am I have received my paper and came to know about the mistake.
    I had also attended today's class and watch the O lab activities.

    Shivank Bhardwaj
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    38

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  5. Received answer sheet and seen our mistakes
    Thank you mam
    Ridhi Johri
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  6. Recieved Bio's paper ma'am. I have noted down my mistakes. Thankyou ma'am

    Gauri Birla
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  7. Recieved biology paper mam
    Thank you mam
    ADITYA Sharma
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    1

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  8. Received my biology answer sheet, seen my mistake And attended today's class.
    Thank you Ma'am
    -Jhanvi bhardwaj
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  9. Received biology answer sheet seen my mistake watched Olab activities and attended today's class

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  10. Received the paper, seen my mistakes and attended O Labs activity
    Daksh Rustagi

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  11. Received biology answer sheet And attended today's class.
    Devashish Kaushik
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  12. I have received biology answersheet
    And attended todays class
    Uttkarsh

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  13. Received biology answer sheet and attended todàys class
    Aryan chadha

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  14. Attended today's class and also received bio answer sheet. Watched O lab activity in the class
    Anshika Rai
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  15. I have attended today's class and watched Olab activities.
    Vani kapoor
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  16. I ve got the paper, thanks mam 🌹

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  17. I ve got the paper, thanks mam 🌹

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  18. I've attended today's class and got the paper, thankyou mam.
    Anushka Aggarwal
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  19. 🙏I have got the paper mam thanks mam 🌹
    Tanishtha gupta X-C

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  20. I have attended today's class and I understood properly.
    Anubhav Gupta
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    13

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  21. Mam I attended class today and understood the experiment done today
    Dhruv Manchanda
    Roll no-22

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  22. O lab activity was awesome
    Thanks mam

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  23. MAM I ATTENDED TODAYS CLASS ,EXPERIMENTS WERE REALLY GREAT
    VAIBHAV GUPTA
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  24. Mam lab activities. Were wonderful
    Tanishtha gupta X-C

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  25. Mam I done whole lab activities and received my paper
    Dhruv Manchanda
    10-C

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  26. The OLAB activities done in the class today was exceptionally wonderful
    There were lots of fun . THANKYOU Mam for this activity
    Pranav Deol
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  27. O LAB ACTIVITY WAS WONDERFUL AND THANK YOU MAM FOR SHARING OUR PAPER
    BHOOMI BHURANI
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  28. Mam I have attended today’s class and o lab activities were wonderful and beautifully explained and I have received the paper
    Chaitanya Bhardwaj
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  29. O lab activity was wonderful
    Bhaavya garg
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  30. Mam I have attended today's class and was able to understand the experiment. And experiments was wonderful.

    And thank you mam for mailing my paper. I had seen my mistakes and will do more hardwork in next exam.

    Ali Rehman Ansari
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  31. Ma'am I have attended today's class and the o lab activities were wonderful.
    Aahana Anand
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  32. Mam I attended today's class and experiments were wonderful!!!
    Shreya Malhotra
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  33. O lab activity was awesome.Thank you so much mam
    Saloni gupta
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  34. O lab activity was a great source of understanding
    Akshat Sipani
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  35. Mam I have attended class today and understood the experiment done today.I have recieved my paper as well.
    Ishita Shrivastava
    10th C

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  36. I have received my paper and also O lab activities were wonderful
    Bhumika Gupta
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  37. Mam I have attended today's class and O lab activities were very informative. Thank you mam for sharing our paper.
    Abhinav Maurya
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  38. Mam I have attended today's class and o lab activities were wonderful.
    Priyanshu Pawar
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  39. Mam I have attended today's class and was able to understand the experiment. And experiments was wonderful.
    And thank you mam for mailing my paper.
    Aakriti Arya
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  40. Ma'am I attended today's class and understood the experiment. Also thank you for checking the papers and mailing them to us.
    Anika Kapoor
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  41. Mam I have attended the class today for O Lab Activities. Recieved my biology paper.
    Thanks mam!
    Chehak Oberoi
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  42. Ma'am I attended today's class and understood the OLAB experiment and papers are received .
    Thank You mam
    ADITYA Sharma
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  43. Mam I have attended today's class. Understood o-lab activities and recieved my paper.
    Thankyou mam
    -Jhanvi bhardwaj
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  44. Mam I have attended today's class and understood the O lab activities and received my paper
    Thank you ma'am
    Ridhi Johri
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  45. Thank you ma'am for your great efforts.

    I have attended today's class and seen the O-Lab Activities and came to know about my marks.
    Thank you so much mam.

    Shivank Bhardwaj
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  46. O lab Activity done today and I was present in today's class
    Aditya kathuria
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  47. O lab activity done today and also got my marks
    Aarushi goyal
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  48. ‘O’ Lab activity and know about the marks of exam. Muskan. X-A

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  49. Got my marks and seen the O LAB activity
    shreya narula
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  50. Got my marks thankyou mam and O lab activity seen
    Tanya kaushik
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  51. Mam I have attended the class today for O Lab Activities. Recieved my biology paper.
    Thanks mam
    X-A
    Tanish

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  52. Attended the class, olab activity done, and got my biology marks. Thank you
    X-A
    Prabhleen

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  53. enjoyed the OLAB activity
    shreya narula
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  54. O lab activity done today and also got my marks.
    Palak goel
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  55. Tkankyou mam for showing stickers exam result. Muskan x-A

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  56. Thank you mam
    Palak Goel
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  57. I have attended today's class and watched Olab activities.
    Vani Kapoor
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  58. O lab activity was awesome mam
    Akshay goel
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  59. I have seen the sample paper and am completing the notes.
    Anika Kapoor
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  60. I have seen sample paper and thank you for notes
    Saloni gupta
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  61. Thankyou mam for these notes.
    Gauri Birla X-G

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  62. Mam i hv seen these notes will complete by today m attending the class thanks for guidance.
    ashpreet kaur
    ix-c

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  63. Mam I have seen these notes and writing down the notes and I attended today's class. Gateek Madan IX-C

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  64. Stuti Sharma
    Mam thankyou for giving these notes, they are truly helpful and I have competed my all my work

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  65. Thank you mam
    I have attended today's class and understood all the topics done till now.

    Shivank Bhardwaj
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  66. I have attended Maths exam
    Sanya
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  67. Thank u mam for these helpful notes
    Tanish Mittal
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  69. I have attended today's hindi exam
    It was easy
    Sanya
    X-G

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  70. Today I am very excited for my science class.
    Diya arora

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